Define $(f_n)_{n\geq1}$ such that $f_n=sin(x+n)$, where this sequence is defined on $\mathbb{R}$. I know that Arzeli-Ascoli cannot be helpful here since $\mathbb{R}$ is not compact, so is there a way of testing the existence of converging subsequence?
2026-02-24 00:46:30.1771893990
Does this sequence of functions have a converging subsequence?
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If you are talking about pointwise convergence the answer is YES: For each $N$ there is a subsequence which converges pointwise (even uniformly) on $[-N,N]$. Hence we can take a diagonal subsequence which converges for all $x$.
There is no subsequence which converges uniformly: if $|sin (nx)-\sin (mx)| <1$ for all $n , m >N$ for all $x$ we can get a contradiction by taking $x=\frac {(2k+1) \pi} {2n}$ and $m=2n$ with $k$ large enough.