Does "$X$ is independent with $Y$" implies "$\mathbb{E}[X|Z]$ is independent with $Y$"?

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Suppose two random variables $X$ and $Y$ are independent. Does this imply that for any random variable $Z$, $\mathbb{E}[X|Z]$ is independent with $Y$?

The above seems very intuitive to me, but I feel it's hard to prove rigorously using the definitions...


Answered (which is No) by @AlexL in the comments (thanks AlexL!).