$$ \frac{5}{2x-3} - \frac{3}{(2x-3)^2} $$
I have to simplify
So I had the minimun common multiple in
$$(2x-3)^2$$ which is $$(2x-3)(2x-3)$$
Then I divide the first fraction denominator by my term, then multiply it by 5, ends in 10x-15. Then I divide the second fraction's denominator by my term, ending in -3.
$$ \frac{10x-15-3}{(2x-3)(2x-3)} $$
After making calcs, I end with:
$$ \frac{10x-18}{4x^2-12x-9} $$
Which seems to be a completely different graphic in Geogebra.
Geogebra's Simplify function gives a very "unsimplified" result for my original formula.
Am I doing something wrong?
Your only error is in the development of $(2x-3)^2$, which is $$ (2x-3)^2=4x^2-12x\mathbin{\color{red}+}9 $$