double expectation proof

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my question is

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Why multiply f(x)?

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If $M$ is some discrete R.V., then $E[M]$ is the sum of all the different values $M$ can take, weighted by the probabilities. So $$E[M]=\sum_m m\times P(M=m)$$Here, $m(x)$ is some continuous distribution, so the sum is replaced by an integral.