I was not able to draw figure for a question.
Question was
From a point of intersection of two circles, the lines to the centers of similitude bisect the angles between the radii of the circles.
Thanks in advance......
2026-03-26 01:01:19.1774486879
Drawing a figure in advanced geometry.
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I think this is what they mean:
$C$ is the centre of similitude; $D$ is a point of intersection of the two circles; and $AE$ and $BF$ are radii through $D$. I think they want you to prove that $DC$ intersects angle $EDB$. But it could have been clearer.
(I don't even know whether it's true, but it looks plausible!)