Let $Y(t) = Ae^{j\phi} + W(t)$, where $\phi \sim unif[-\pi,\pi]$ and $W \sim \mathcal{N}(0,\sigma^2)$. What is the probability distribution of $|Y(t)|$ ?
If $\phi$ was deterministic, i.e. a constant value, the distribution of $|Y(t)|$ would be $|Y(t)| \sim Rice(A,\sigma^2) $. However, in my case $\phi$ is not a deterministic value, so the PDF might change.
I have simulated in MATLAB this, comparing the case where $\phi$ is a uniformly distributed random variable and three more cases where $\phi = \{ \phi_1, \phi_2, \phi_3 \}$ are constant values.
Matlab code:
phi = 0:pi*1e-3:1e3*pi; % phase vector
phi1 = phi(randi(length(phi)));
phi2 = phi(randi(length(phi)));
phi3 = phi(randi(length(phi)));
A = 2.8e-6; % signal amplitude
x = A*exp(1i*phi); % signal vector
x1 = A*exp(1i*phi1); % signal vector 1
x2 = A*exp(1i*phi2); % signal vector 2
x3 = A*exp(1i*phi3); % signal vector 3
sigma = 2.5e-5; % noise variance
w = sigma/sqrt(2)*(randn(1,length(phi)) + 1i*randn(1,length(phi))); % noise signal
y_th = x+w; % received signal
y_th1 = x1+w; % received signal 1
y_th2 = x2+w; % received signal 2
y_th3 = x3+w; % received signal 3
figure();
subplot(2,2,1); hist(abs(y_th),200); title('\phi uniformly distirbuted');
subplot(2,2,2); hist(abs(y_th1),200); title('\phi = \phi_1');
subplot(2,2,3); hist(abs(y_th2),200); title('\phi = \phi_2');
subplot(2,2,4); hist(abs(y_th3),200); title('\phi = \phi_3');
Matlab results:

As you can see in the final results the PDFs of the signal with $\phi$ as a random variable and of the signals with $\phi$ as deterministic values are really close to. Are they equivalent? Is it fine to assume that?
Really appreciate your help :)