Evaluate $\int_{\mathcal{C}}\frac{\sin z}{z-\pi/2}\,\mathrm{d}z$

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Problem.1) Evaluate $\displaystyle \int_{\mathcal{C}}\frac{\sin z}{z-\pi/2}\,\mathrm{d}z$, given that $\mathcal{C} : |z| = \pi/2$

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Use Cauchy's integral formula.

$$\int_{|z|=a} \frac{f(z)}{z-a}dz = 2\pi i f(a) $$

For your question $f(z) = sin(z)$

So answer to your question is $2\pi i sin(\frac{\pi}{2}) = 2\pi i$