Evaporation Formula

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I am currently working on a project that has been passed down several times, along the chain of responsibility. This project is develop a Calculator that, after entering set amount of data, will let us know how extreme the circumstances are and whether we need to inform that proper government agencies/entities.

Now, specifically, I am looking for a generalize formula to calculate Evaporation rate of Hazardous Substances. My main thought was to come up with an evaporation formula for water, then substitute density, vapor pressure, whatever else I would need, in order to get an approximation of what was spilled.

An Engineering student had given us some formulas but they don't look quite right, nor can I verify the legitimacy of the formulas.

Here are some of them:

General Evaporation Rate Formula
$\frac {(0.284 \cdot (\mathbf {Average\ windspeed})^{0.78} \cdot (\mathbf {molecular\ weight})^{0.667} \cdot (\mathbf {surface\ area}) \cdot (\mathbf {vapor\ pressure})}{(82.05 * (\mathbf {temperature\ in\ K})}$

Evaporation Rate from Berm
$\frac {(0.284 \cdot (\mathbf{Average\ windspeed})^{0.78} \cdot (\mathbf{molecular\ weight})^{0.667} \cdot (\mathbf{surface\ area}) \cdot (\mathbf{Surface\ Area}) \cdot (\mathbf{vapor\ pressure})}{(82.05 * (\mathbf{temperature\ in\ K}))}$

*****Surface Area Equations******
Scenario 1:
$l \cdot w = A$
$A - (\pi \cdot (\frac {\mathbf{Diameter\ of\ tank\ in\ berm}}{2})^2 \cdot (\mathbf{How\ many\ tanks\ in\ berm}))$
Scenario 2:If we have 3 tanks in the berm
$l \cdot w = A$
$A - (\pi \cdot ((\frac {\mathbf{Diameter\ of\ tank\ in\ berm}}{2})^2)) \cdot (\mathbf {Number\ of\ tanks\ in\ berm,\ of\ that\ diameter}))-\pi (\frac{(\mathbf{Diameter\ of\ tank\ in\ berm})}{2})^2 * (\mathbf {Number\ of\ tanks\ in\ berm,\ of\ that\ diameter}))- \pi(\frac{(\mathbf{Diameter\ of\ tank\ in\ berm})}{2})^2 \cdot (\mathbf {Number\ of\ tanks\ in\ berm,\ of\ that\ diameter}))$

Now this isn't pretty, so my apologies, but I am new to this section of forums.

If anyone could give me some insight or direction, that would be most appreciated.

Thanks,