I have found the statement as in the title of this post on wikipedia, however, there is no reference for its proof. How does one prove it?
Every finite Galois extension of $\mathbb{Q}_p$ has a solvable Galois group.
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Let $K/{\Bbb Q}_p$ be a Galois extension and $k$ the residue field of $K$. As Galois actions preserve integrality there is an induced action of $G$ (the Galois group) on ${\frak O}_K$ fixing $\Bbb Z_p$; it futhermore fixes powers of the maximal ideal of ${\frak O}_K$ and so induces an action on $k$ over ${\Bbb F}_p$, and more generally $G$ acts as automorphisms of ${\frak O}_K/{\frak m}^i$ for all $i\ge0$. We define $G_i:=\ker(G\to{\rm Aut}({\cal O}_K/{\frak m}^{i+1}))$ for $i\ge-1$ to be the ramification groups of $K/{\Bbb Q}_p$. We have $G_{-1}=G$, and $G_0$ is called the inertia group of the extension, while $G_1$ is called the wild inertia group. There is now a ramification filtration
$$G=G_{-1}\trianglerighteq G_0\trianglerighteq G_1\trianglerighteq G_2\trianglerighteq\cdots $$
Via $1$st iso thm there is a canonical isomorphism $G/G_0\cong{\rm Gal}(k/{\Bbb F}_p)\cong C_f$ where $f$ is the residue degree of $K/{\Bbb Q}_p$ (that is $f=\dim_{\,{\Bbb F}_p}k$). Then, if $\pi$ is a uniformizer (principal generator of ${\frak O}_K$'s max ideal ${\frak m}$), the map $\sigma\mapsto \sigma(\pi)/\pi$ is an injective group homomorphism $G_i/G_{i+1}\to U_i/U_{i+1}$ where $U_i:=1+{\frak m}^i$ are the higher unit groups (under multiplication). The quotient $U_0/U_1$ is clearly $k^\times\cong C_{p^f-1}$, and $U_i/U_{i+1}\hookrightarrow {\frak m}^i/{\frak m}^{i+1}\cong k^+\cong C_p^f$ hence is elementary abelian.
Thus $G_1\hookrightarrow G_0\hookrightarrow G$ where $G_1$ is a $p$-group (hence solvable), $G_0/G_1$ is cyclic of order dividing $|k^\times|=p^f-1$ and $G/G_0$ is cyclic of order $f$. Therefore, $G$ is a solvable group.
For more detail and some proofs, I like Boston's The Proof of Fermat's Last Theorem's Chapter 3, from Definition 3.6 up to Corollary 3.9 (which is the desired claim). (The link is an official pdf.)
This follows from the theory of ramification groups (in the "lower numbering").