Exact sequence of cohomology $0 \rightarrow H^{n - 1}(X) \rightarrow H^{n - 1}(Y) \rightarrow \mathbb{Z}^2 \rightarrow \mathbb{Z} \rightarrow 0$

Question

Say I have the following exact sequence of cohomology: \begin{align*} 0 \rightarrow H^{n - 1}(X) \rightarrow H^{n - 1}(Y) \rightarrow \mathbb{Z} \oplus \mathbb{Z} \rightarrow \mathbb{Z} \rightarrow 0 \end{align*} Is there anything I can say about the relationship between $H^{n - 1}(X)$ and $H^{n - 1}(Y)$? Thanks!