Noetherian property is redundant?

100 Views Asked by At

I believe everyone knows "in a local Noetherian local commutative ring, a f.g. module is free if and only if it is flat".

The proof is in the question flat f.g. modules over a commutative, local, Noetherian ring are free . We only need to notice that $k \otimes F$ anf $k\otimes M$ are vectors space of the same finite dimension.

Anyway, I do not see where the Noetherian property is used. NAK lemma does not require it.

Thank you for your help.