Exponential and Logarithm Derivatives

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I am trying to understand the derivative of the function $G(d)=a^d$. I am told it is the following (lecturers comments on my work)

$$ \frac{\partial}{\partial d}(a^d) = \frac{\partial}{\partial d}(e^{d\log a}) = (\log a)a^d $$

I'm not sure where the exponential comes from. Looking at this site the rule is

$$ \frac{\partial}{\partial d}(a^d) = a^d \ln a $$

and converting from $\ln$ to $\log$ does not seem to help. Can someone point me in the right direction?

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The issue is whether the base is the variable or the exponent is the variable. If the base was the variable, i.e., $d^a$ then the derivative would be $a \, d^{a-1}$, applying power rule.

If the variable $d$ is in the exponent, you are dealing with an exponential function. Derivative of $e^x$ is $e^x$, then combining with chain rule, you get the result your lecturer gives.

For details, we want to have an equivalent expression for $a^d$ with $e$ as the base (so that we can use the derivative of $e^x$). If we temporarily let $y=a^d$, taking natural log we get $\ln y = d \, \ln a$, and exponentiating back you get $y = e^{d \, \ln a}$. Now taking the derivative with respect to $d$ (applying derivative of $e^x$ along with chain rule) you get $\frac{dy}{dd} = e^{d \, \ln a} \, \ln a = a^d \, \ln a$

HTH.