How would you go about solving this equation: $x^x=10$.
The much I've figured is $x\ln{x}=\ln{10}$
Take that last equation you have and notice that
$$\log 10 = x \log x = e^{\log x} \log x$$
At this point we can apply the inverse of $ze^z$ to both sides, the Lambert W function.
$$W(\log 10) = W\left(\log x e^{\log x}\right) = \log x$$
which means $x = e^{W(\log 10)}$
We get $x=\frac{\ln10}{\ln x} $ Now use numerical methods to approximate the answer.
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Take that last equation you have and notice that
$$\log 10 = x \log x = e^{\log x} \log x$$
At this point we can apply the inverse of $ze^z$ to both sides, the Lambert W function.
$$W(\log 10) = W\left(\log x e^{\log x}\right) = \log x$$
which means $x = e^{W(\log 10)}$