$f ^{\prime \prime}(x) = f(x) f^{\prime \prime} (x-1) $

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I know the equation

$$ f^{\prime} (x) = f(x) f^{\prime} (x-1) $$

is solved by $f(x) = C$ or by tetration ( $ f(x+1) = \exp(f(x)) $).

So I wonder What are the solutions to

$$g^{\prime \prime}(x) = g(x) g^{\prime \prime} (x-1) ?$$

For $x>1$ and $g^{\prime \prime}(x) > 0$ ??

Any good asymptotics , functional equations , asymptotic functional equations or ... ???