$f '(x) = -f(x)$ and $f(1) = 1$, Solve for $f(2)$

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I am honestly not even sure how to start this problem... My first thought was that $f(2) = 2$ ... But now I don't even know where to go from there.

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Hint: What is $\frac{\mathrm{d}}{\mathrm{d}x}Ce^{-x}$, where $C$ is a real constant?