I want to find the Gaussian prime factors of $(4+3i)$
$$(4+3i)(4-3i) = 25=5^2$$
$$5: (2-i)(2+i)$$ so $$(4+3i)(4-3i) = 25=5^2 = (2-i)(2+i)(2-i)(2+i)$$
That was my answer but the solution says:
$$(2-i)(1+2i)$$
Are both correct is the my solution wrong?