Factorization of the polynomial: $m^2+3m^2n^2-30n^2-10$

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How can we factor the polynomial $m^2+3m^2n^2-30n^2-10$ ?

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$ m^2+3m^2n^2-30n^2-10=m^2(1+3n^2)-10(1+3n^2) =(1+3n^2)(m^2-10)$

This is the answer.

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There are no nontrivial polynomial factors.

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$m^2 +3n^2(m^2-10)- 10$

$m^2-10 + 3n^2(m^2-10)$

$(m^2-10)(1 + 3n^2)$