Find the value of $b(x) \in \mathbb{C}, x\in \mathbb{R}$, so that $$Â=(Â^{*})^{t}$$ with $$Â=i\frac{d}{dx}+b(x)$$
Here, $(f|g)$ is defined by $$ \int_{-\infty}^{\infty} x^{2}f^{*}(x)g(x)dx $$
I have found $Im{b(x)}=\dfrac{1}{x} $, is it correct?
Find the value of $b(x) \in \mathbb{C}, x\in \mathbb{R}$, so that $$Â=(Â^{*})^{t}$$ with $$Â=i\frac{d}{dx}+b(x)$$
Here, $(f|g)$ is defined by $$ \int_{-\infty}^{\infty} x^{2}f^{*}(x)g(x)dx $$
I have found $Im{b(x)}=\dfrac{1}{x} $, is it correct?
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