I'm new to recurrence relations and I'm having trouble figuring out this problem:
Find a recurrence relation for the number of ways to make a stack of green, yellow, and orange napkins so that no two green napkins are next to each other.
Right now I've come up with $$a_n=2a_{n-1}+2a_{n-2}$$ but I'm not sure if this is right.
Any help would be great!
Consider a stack of $n$ napkins. If it ends in non-green, any stack of $n - 1$ came before; if it ends in green, the next to last is non-green, and before those last two there is a stack of $n - 2$. See how many choices you have in each case. Make sure to add initial conditions (numer of stacks with 0 napkins and with 1).