Find all possible values of r such that: nPr = r!

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$$^{n}P_{r} = r!$$ Find all possible values of r.

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You can go back to the definition.

$$^{n}P_{r} = r!\iff \frac{n!}{(n-r)!}=r!\iff \frac{n!}{(n-r)!r!}=1\iff\binom{n}{r}=1.$$