The fact that you're asking for a common ratio probably means that the sequence with terms $b_n$ form a geometric sequence but that's something you should mention. It also helps to show your own effort, ideas or relevant formulas you have seen.
You probably know that $b_n = q \cdot b_{n-1}$ and from this also $b_n = q^{n-1}\cdot b_1$. You know $b_1$ and $b_8$ so use this formula with $n=8$ to get an equation for $q$.
1
user371838
On
Hint:
For a geometric progression with first term $a$ and common ratio $r$, the $n^{\text{th}} $ term is given by: $$b_n = ar^{n-1}$$
The fact that you're asking for a common ratio probably means that the sequence with terms $b_n$ form a geometric sequence but that's something you should mention. It also helps to show your own effort, ideas or relevant formulas you have seen.
You probably know that $b_n = q \cdot b_{n-1}$ and from this also $b_n = q^{n-1}\cdot b_1$. You know $b_1$ and $b_8$ so use this formula with $n=8$ to get an equation for $q$.