Find equal side lengths for isosceles triangle from middle angle and area?

Question

I know that this is a really easy question, but I am looking for the answer to this question:

The area of this isosceles triangle is 5cm squared.

The angle ABC is 22 degrees.

Work out the lengths of the two equal sides of the triangle

Thanks

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Answer 1

from $$5cm^2=\frac{1}{2}x^2\sin(22^{\circ})$$ we get $$x=\sqrt{\frac{10cm^2}{\sin(22^{\circ})}}$$ now you can take a calculator.