I know how to find inverse function if the given function is in the explicit form. Could someone show on this example how to find $f^{-1}$?
Thanks for replies.
I know how to find inverse function if the given function is in the explicit form. Could someone show on this example how to find $f^{-1}$?
Thanks for replies.
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If $x-y=u$ and $x-10y=v$, then $9y=u-v$. Hence $y=(u-v)/9$. Finally, $x=y+u=(u-v)/9+u$. Therefore $$ f^{-1} \colon (u,v) \mapsto (u+(u-v)/9,(u-v)/9). $$