How about the set of all words over $\{a,b\}$ that are either empty or have a different number of $a$'s and $b$'s. So $LL=L^*$ would be all words over $\{a,b\}$, but $L$ itself is not.
Or even simpler, $L=\{w\mid |w|\neq3\}$
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Take $L = 1 + a + a^3a^*$. Then $L^2 = L^* = a^*$, but $L \not= L^2$.
How about the set of all words over $\{a,b\}$ that are either empty or have a different number of $a$'s and $b$'s. So $LL=L^*$ would be all words over $\{a,b\}$, but $L$ itself is not.
Or even simpler, $L=\{w\mid |w|\neq3\}$