FInd the area of the quadrilateral $ABCD.$

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A point moving around a circle $x^2+y^2+8x+4y-5=0$ with center $C$ broke away from it either at the point $A$ or at the point $B$ on the circle and moved along a tangent to the circle passing through the point $D(3,-3).$FInd the area of the quadrilateral $ABCD.$


We can take the point $D$ either on the tangent passing through point $A$ or the tangent passing through point $B$.I took $D$ on the tangent passing through point $A$.Area of quadrilateral $ABCD=$area of triangle $ACD+$ area of triangle $BCD.$I found the area of triangle $ACD=\frac{25}{2}$,but i cannot find the area of triangle $BCD.$

Please help me.

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  1. complete the squares to calculate the co-ordinates of the point C and the radius of the circle.
  2. compute the length CD
  3. Use the fact that the angles at A and B are right angles to calculate the lengths BD and AD
  4. Area = $\frac 12 AC \times AD + \frac 12 BC \times BD$