I think I'm supposed to use $z = (X - \bar X)/S$ but I'm not sure how to apply it properly to this problem.
Kyle got an 8.25 on his previous test while the average score was a 7.2 and the standard deviation was 0.8.
On another test he got a 7.25 and the standard devation was also 0.8. What was the average score for the second test?
I assume it's the same sample size but I'm not sure if that would matter. So attempting to use the equation I listed I tried doing the following:
$$z = \frac{8.25-7.2}{.8} = 1.3125$$
Then using that apply it to the second test (after shifting around the equation to solve for the average):
$$\bar X = -((.8 \times 1.3125)-7.25) = 6.2 $$
So my guess is that the average would be 6.2 but I haven't done this is a long time and don't recall if what I did is correct.
As commented on the question, the assumption has to be made that Kyle is the same number of standard deviation units from the mean. Therefore my calculation is correct. If that assumption cannot be made then the probably is not possible to solve with the given information.