Find the coefficient of $x^{17}$ in the expansion of $ x^5\cdot (1+x^2)^{12}$

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Find the coefficient of $x^{17}$ in the expansion of $ x^5\cdot (1+x^2)^{12}$

Help to solve this MCQ problem. I have tried a lot of times but I got the wrong answer.

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Hint. Recall the Binomial Theorem. What is the coefficient of $x^{12}$ of $$(1+x^2)^{12}=\sum_{k=0}^{12}\binom{12}{k}(x^2)^k\;?$$