I want to write A(n) in terms of B(n) but nothing seems to work I can find the appropriate pattern.
n A(n) B(n) 1 1 0 1 1 1 2 3 1 3 5 2 4 9 3 5 15 5 6 25 8 7 41 13 8 67 21
I want to write A(n) in terms of B(n) but nothing seems to work I can find the appropriate pattern.
n A(n) B(n) 1 1 0 1 1 1 2 3 1 3 5 2 4 9 3 5 15 5 6 25 8 7 41 13 8 67 21
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Hint If $A(8)$ is $67$ and not 61, as in your table, compare $$A(n+1)-A(n) \mbox{ with } 2B(n)$$
Hint 2 $\sum_{k=1}^n A(k+1)-A(k)$ is telecopic. Use $$\sum_{k=1}^n A(k+1)-A(k)=2 \sum_{k=1}^n B(k)$$