How would I start this, I know that the normal vector is $\left<2,0,-1\right>$ and the dot product of the normal and the point $Q$ is $-3$.
2026-03-30 01:48:03.1774835283
Find the equation of the plane that contains the point $Q(1,2,5)$ and is parallel to the plane $2x-z= 1$.
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You don't need the dot product or vector product. You know, because the two planes have to be parallel, that the second plane has as equation:
2x - z = d.
Filling in the given point Q and solving for d yields the answer.