Find the given inverse Laplace transform.

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This problem has really got me stumped, and I thought that I had it solved, but I am guessing I had messed up somewhere. Any help would be much appreciated.

Given:

$$\mathrm{L}^{-1}\left(\frac{16s}{16s^2+1}\right)$$

The answer I initially got was $\cos\left(\frac{t}{16}\right)$, but that is incorrect.