Find the isolated singularities of $\dfrac{3z}{z^3+1}$ and calculate their residues using the 'g/h rule'
I understand that $z=-1$ is a singularity but I'm not sure about the others or how to apply the gh rule to this function.
Find the isolated singularities of $\dfrac{3z}{z^3+1}$ and calculate their residues using the 'g/h rule'
I understand that $z=-1$ is a singularity but I'm not sure about the others or how to apply the gh rule to this function.
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HINT:
$$z^3=-1\implies z^3=e^{i(2n-1)\pi}$$
for $n=0,1,2$.
Alternatively, write $z^3+1=(z-1)(z^2+z+1)$ and find the roots of the quadratic.