So I was just messing around with finding the maximum and minimum values of functions, and I came across this:
$$ \text{Find the maximum value of} \,\, f(x)=\frac1{x^{2x^2}}.$$
Any ideas?
2026-05-14 13:46:38.1778766398
Find the maximum value of the function
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Hint. Assume $x>0$. Then you get $$ f'(x)=\frac{-2x\times (1+2 \ln x)}{x^{2 x^2}} . $$ Can you take it from here?