Given a pentagon $ABCDE$ inscribed in a circle with centre $O$. Three of the interior angles are $95^°$, $130^°$ and $138^°$. Find angle $x$ and $y$.
I'm quite sure that $x$ and $y$ can be found as the other three angles are fixed, so $x$ and $y$ should also be fixed by the circle arc.
This question contains an error as $x$ and $y$ are not fixed. There are many ways to draw the pentagon with 3 same angles.