$$24x^{5} - y^{2} + 5 = 0$$
Hint: consider the equation mod 8
I've been stuck on this question all day, any help would be appreciated!
2026-04-17 19:41:39.1776454899
Find the set of integer solutions to the following equation
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Mod $8$, it’s $y^2\equiv5.$
Is $y^2\equiv5$ for $y\equiv0, 1, 2, 3, 4, 5, 6, $ or $7$?