Find the values a and b such that the function is differentiable

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$f(x)=\frac{x}{(1+e^{(1/x)})}$ for $x<0$ and $ax^2+b$ for $x\geq 0$

so I know that if function is differentable at some point $x=0$ for piecewise functions their

limits have to be equal but im confused about this $e^{(1/x)}$ because you cant divide by $0$ and im not sure what to do