Find the Var[X] for the continuous random variables with given joint probability density function.

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In this question I was supposed to find the $E[X]$ and $\text{Var}[X]$.

I found $E[X] = 0.6$ and $\text{Var}[X] = 0.3696$ but when I checked the answer it shows that my $E[X]$ is correct but my $\text{Var}[X]$ is wrong!!!

What is the correct answer for $\text{Var}[X]$?

ThankYou in advance.

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Integrating

$$\int_x^{\infty}f(x,y)dy=f_X(x)=\frac{125}{2}x^2e^{-5x}=\frac{5^3}{\Gamma(3)}x^{3-1}e^{-5x}$$

we immediately realize that

$$X\sim \text{Gamma}[3;5]$$

Thus

$$\mathbb{E}[X]=\frac{3}{5}$$

and

$$\mathbb{E}[X]=\frac{3}{5^2}$$

wihtout any other calculations