I have a triangle with coordinates (0,0), (1,2) and (1,0). Is the area of this triangle same as finding the integral of the function $y=2x^2$ and substituting the value of x=1 and y=2? Because what i understood by reading about integral is that it can find the area under the slop with which the function to be integrated is defined. I have tried this way and i am getting different values for the integration method and original area. Where am i wrong?
2026-03-26 06:32:46.1774506766
Finding area of a triangle with integration
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The function to integrate is $y=2x$, not $y=2x^2$. The hypotenuse is a straight line, not a parabola. And you integrate between 0 and 1. Draw a figure. It will help you understand.