Finding cos(a-B) using tan a = 4/3 in quad III and cos B = 12/13 in quad IV

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Really stuck with this problem, I need help with this asap.

To find cos(a-B), I'm supposed to use:

tan a = 4/3, with a in quadrant III

cos B = 12/13, with B in quadrant IV

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I have shown the relevent identities . I hope this helps answer your question.