Given: circle with equation $(x-2)^2+(y-1)^2=4$. How to find equation of tangent line to the circle that intersects the origin?
I easily found out that one of the tangents is $x=0$.
Given: circle with equation $(x-2)^2+(y-1)^2=4$. How to find equation of tangent line to the circle that intersects the origin?
I easily found out that one of the tangents is $x=0$.
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Clearly one tangent is $x=0$, as you say. Reflect it in the line $y=x/2$ which passes through the origin and the centre of the circle and you get $y=-3x/4$ as the other tangent.