Find $\dfrac{890×12.34×0.0637}{87.35×2.274}$ by using logarithms.
$$\log(890)=2.9494,\ \log(12.34)=1.0913,\ \log(0.0637)=-2.8041,\\\log(87.35)=1.9412,\ \log(2.274)=0.3568,$$ therefore the calculation becomes $$(2.9494+1.0913-2.8041)-(1.9412+0.3568)=-1.0614\\\log^{-1}(-1.0614)\approx0.1152.$$ But this is the wrong answer because just plugging in the original numbers in a calculator gets $3.522$. I can't see where I made a mistake. Thanks.
Since you mentioned that you use a table, when you look at the value for $0.0637$, we viewed it as $6.37\times 10^{-2}$.
Taking logarithm, we have $$-2 + \log(6.37)=-2\color{red}+0.8041=-1.1959$$