I need help on a problem regarding a parallelogram and finding an altitude on it. The problem goes like this:
Given: $EI$ and $EY$ are altitudes of the parallelogram $EMLJ$. $EJ=20$; $EM=30$; $EI=24$. Find $YL$
I was able to find $MI$ because of Pythagorean triples which resulted in finding $IL$ with subtraction if that helps give any leads or make the picture more understood. Thank you so much!

hint
$$YL=LJ-YJ=30-YJ $$
$$YJ=20\cos (\theta) $$
$$\cos (\theta)=\frac {18}{30}=\frac {3}{5}$$
You will get $18$.