I have to find an optimal mixed strategy for the 'column' player, who mixes with the probabilites $q_1,q_2,q_3$. What is known is the optimal mixing of the 'row" player. The game is a zero-sum game, each entry represents Row's gain, and Column's loss.
$\begin{bmatrix} &q_1 &q_2 &q_3\\ p=\frac{4}{7}& 4&5&2\\ 1-p=\frac{3}{7}&3& 1 &5 \end{bmatrix}$
I thought I should calculate the value of the game, so I wrote:
$\frac{4}{7}(4q_1+5q_2+2q_3)+\frac{3}{7}(3q_1+1q_2+5q_3)=$
$=\frac{25}{7}q_1+\frac{23}{7}q_2+\frac{23}{7}q_3$
But I don't know how to proceed.
Given the question as you've clarified it, [EDITED FROM HERE ON TO CORRECT FOR MY FAILURE TO READ THE UPDATED QUESTION CAREFULLY ENOUGH], yes in response to your comment, you want to minimize Row's payoff by having Column zero out $q_1$ and pick any $q_2$ and $q_3$ that add up to 1. This is because those two have the same coefficient, 23/7, and it's less than 25/7.