Finding $P(XY \le a)$ when $x<y$ and the distribution of both is uniform

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Let $X$ and $Y$ be random variables with joint pdf

$$f_{XY}(x,y) = \begin{cases} 1, &0 < x <1,\ \ x < y < x+1 \\ 0, & \text{otherwise} \end{cases}$$

Find $P(XY \le a)$

I am going to solve this using the CDF method with integration.

Based on the information given, my setup is the following:

$$0 < x < y < 1 \\ x < y < x+1 < 2 \\ xy < a$$

I will make a diagram, where the blue curve represents an example of $0<a<1$, and the green curve represents an example of $1<a<2$:

enter image description here

For $0<a<1$, I will integrate:

$$\int_0^a \int_0^{\min \{{a \over y}, \ y\}}\, dx \ dy $$

For $1<a<2$, I will integrate:

$$\int_0^2 \int_0^{\min \{{a \over y},\ 1 \}}\, dx \ dy $$

My question is twofold:

  1. Are my steps correct so far, and if not, where am I going wrong?

  2. Is there a simpler way to do this?