Finding real-numbers subsets which are isomorphic to some ordinals.

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For example I know that $A=\{5-\frac{1}{n}\}_{n \in \mathbb{N}}\cup\{6,7,8,...,k+6\}$ is isomorphic to $\omega + k$ for $k<\omega\;$ because I know I can look at $\omega + k\;$ as $\; B=(n\times\{0\})_{n\in\mathbb{N}}\cup(j\times\{1\})_{6\leq j\leq k+6} $ with the lexicograpic order.

However, If I wanted to find real numbers subset which is isomorphic to $\omega + \omega + k\;$ for $k<\omega\;$

How could I do that? how can I visualize this ordinal in order to give it a mataching real subset.

As well as for $\omega + \omega + \omega + ... + \omega$ (n times)

I would love to get some examples and intuition if possible! thanks.

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If $\alpha$ is a countable ordinal, then there is an injective map $f:\alpha\to\omega$, and $$\xi\mapsto\sum_{\eta\lt\xi}2^{-f(\eta)}$$ is an order embedding of $\alpha$ into $\mathbb R$.

A similar argument shows that every countable linear order is embeddable in $\mathbb R$. A different argument is needed if you want to show that every countable linear order is embeddable in $\mathbb Q$, or that every countable ordinal is order-isomorphic to a closed subset of $\mathbb R$.

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{ k + n : k + 1 - 1/n : n,k in N, n /= 0 }
is order isomorphic to $\omega_0$ × $\omega_0$.