Finding the area of an open rectangular tank

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I tried approaching this as a normal rectangle, but my answer doesn't seem to be in the options. Here's the question -

An open rectangular tank: 4m long, 3m wide and 4m high is made out of a thin metal sheet. Find the area of the metal sheet used in its construction.

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Sine, the tank is open say at the top then surface area of the tank $$=(\text{total surface area of lateral walls of the tank })+\text{(area of rectangular base of the tank})$$

$$=2(\text{(length)}\times(\text{height})+\text{(width)}\times(\text{height}))+\text{(length)}\times(\text{width} )$$

Area of total surface of the tank $$=2(4\times 4+3\times 4)+3\times 4=2(28)+12=68 \ m^2$$