Finding the centre of a conic section with $xy$ term equal to $0$

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In my textbook I am told about a conic section with equation:

$$9x^2 -4y^2 -54x - 16y + 29 = 0$$

and it mentions in passing that since the $xy$ term is $0$ then the centre is:

$\frac{54}{2\times9}, \frac{16}{-2\times 4}$

Presumably they are implicitly using a rule that looks like:

$α = \frac{-D}{2A}, β=\frac{-E}{2C}$ where $(α,β)$ is the centre of a conic section with general form

$$Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0$$

But I've not come across a rule like that. So my question is firstly, am I even inferring the correct rule? And secondly, why does this work?