given the joint pdf $f(x,y) = $
$$k e^{-\frac12(x^2-2xy+5y^2)},$$
find $k.$
I understand that there is some trick to computing $k$ using properties of the multivariate normal distribution, but have no clue where to start.
given the joint pdf $f(x,y) = $
$$k e^{-\frac12(x^2-2xy+5y^2)},$$
find $k.$
I understand that there is some trick to computing $k$ using properties of the multivariate normal distribution, but have no clue where to start.
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$$\int_{-\infty}^\infty e^{-\frac 1 2 (x^2-2xy+5y^2)} \, dx \, dy =\int_{-\infty}^\infty e^{-\frac 1 2 ((x-y)^2+4y^2)} \, dx \, dy. $$
Integrate with respect to $x$ first and note that
$$ \int_{-\infty}^\infty e^{-\frac 1 2 ((x-y)^2)} \, dx =\int_{-\infty}^\infty e^{-\frac 1 2 x^2} \,dx =\sqrt {2\pi}. $$
Now $$\int_{-\infty}^\infty e^{-2y^2}=2\sqrt {2\pi}$$ as seen by the substitution $y=2z$. Hence $$\int_{-\infty}^\infty e^{-\frac 1 2 (x^2-2xy+5y^2)} \, dx \, dy =4\pi$$ and the value of the constant $k$ is $\dfrac 1 {4\pi}$.