Im trying to find the inverse of this function
$$x \mapsto\frac {113^x - 1}{112}\def\comment#1{}\comment{(pow(113.0, x)-1.0)/112.0} $$
But it always turn up incorrect. Can someone point me in the right direction?
$$y=\frac{113^x-1}{112}$$ $$112y+1=113^x$$ $$x\log 113=\log(112y+1)$$ $$x=\frac{\log(112y+1)}{\log 113}$$
Copyright © 2021 JogjaFile Inc.
$$y=\frac{113^x-1}{112}$$ $$112y+1=113^x$$ $$x\log 113=\log(112y+1)$$ $$x=\frac{\log(112y+1)}{\log 113}$$