Can anyone help me in finding the sum of digits without manual multiplication?
2026-03-29 13:27:22.1774790842
Finding the sum of digits of a large number
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We want to compute $$5\cdot5^2\cdot5^6\cdot5^{24}\pmod9$$
We have $$\begin{align} 5^2&=25\equiv-2\pmod9\\ 5^6&=(5^2)^3\equiv(-2)^3\equiv-8\equiv1\pmod9\\ 5^{24}&=(5^6)^4\equiv1^4\equiv1\pmod9 \end{align}$$
Take it from here.