What's the value of $n$ in the following equation?
$$2(2n-4)!= (n-4)!(n+2)!$$
I've tried coming up with an equivalent combination and expanding $(n+2)!$ but that didn't get me anywhere.
2026-04-03 18:01:56.1775239316
Finding value of unknown in factorial equation
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Let $n = 6$ $$2(2n-4)! = (n-4)!(n+2)!$$ $$\implies 2(8!) = 2!(8!)$$ Since the left hand side increases faster than the right, this is the only solution.